10c^2+23c+12=

Solution for 10c^2+23c+12= equation:

Simplifying
10c2 + 23c + 12 = 0

Reorder the terms:
12 + 23c + 10c2 = 0

Solving
12 + 23c + 10c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(3 + 2c)(4 + 5c) = 0

Subproblem 1
Set the factor '(3 + 2c)' equal to zero and attempt to solve:

Simplifying
3 + 2c = 0

Solving
3 + 2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 2c = 0 + -3
2c = 0 + -3

Combine like terms: 0 + -3 = -3
2c = -3

Divide each side by '2'.
c = -1.5

Simplifying
c = -1.5
Subproblem 2
Set the factor '(4 + 5c)' equal to zero and attempt to solve:

Simplifying
4 + 5c = 0

Solving
4 + 5c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 5c = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 5c = 0 + -4
5c = 0 + -4

Combine like terms: 0 + -4 = -4
5c = -4

Divide each side by '5'.
c = -0.8

Simplifying
c = -0.8
Solution
c = {-1.5, -0.8}